A gas occupies a volume of 0.6 L at 10.1 kPa. What volume will the gas occupy at 101 kPa?
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"How to prove this ?
#2|k^2# then #2|k# for some #k\inZZ#"
1 Answer
Explanation:
Use the equation for Boyle's Law
#P_1V_1 = P_2V_2#
Plug in your values to get
#("10.1 kPa") xx (".6 L") = ("101 kPa") xx V_2#
#[(10.1cancel("kPa"))(".6 L")]/(101cancel("kPa"))= V_2#
#V_2 = ".06 L"#
