In the reaction #4Fe + 3O_2 -> 2Fe_2O_3#, how many grams of #Fe_2O_3# are produced from #73.2g# #Fe#?

Question

2665 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-27T09:38:30

104.6 g of #"Fe"_2"O"_3#.

This can be solved through dimensional analysis.

Atomic Masses:

#"Fe = 55.85 g/mol"#
#"O = 16.00 g/mol"#

Formula Mass:

#"Fe"_2"O"_3 ="159.69 g/mol"#

#"Moles of Fe" =73.2cancel("g Fe") xx ("1 mol Fe")/(55.85cancel("g Fe")) = "1.31 mol Fe"#

#"Moles of Fe"_2"O"_3 =1.31 cancel("mol Fe") xx ("2 mol Fe"_2"O"_3)/(4cancel("mol Fe")) = "0.655 mol Fe"_2"O"_3#

#"Mass of Fe"_2"O"_3 = 0.655cancel("mol Fe"_2"O"_3) xx ("159.69 g Fe"_2"O"_3)/(1 cancel("mol Fe"_2"O"_3)) = "104.6 g Fe"_2"O"_3#