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Question #2128f

1 Answer

Feb 24, 2016

#x=2#

Explanation:

#x^2 + y^2 = 8#
#x-y =4#

#:.y = x-4#

substituting this back into the first equation gives
#x^2 + (x-4)^2 = 8#

#x^2 +x^2 - 8x +16 = 8#
#2x^2 - 8x +8 =0#
#x^2 -4x +4 = 0#
#(x-2)^2 = 0#

#:.x=2#

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