How do you solve $2 x^{2} + 5 x = - 4$ $2x^2+5x= - 4$ using the quadratic formula?

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Answer 1 · 2016-02-19T20:39:48

( $- b + or -$ $-b + or -$ $\sqrt{}$ $sqrt($ b^2 -4(a)(C)))÷(#2a) quadratic formula must equal zero

x

− $b^{2}$ $b^2$ ±√b−4ac

2a

move 4 to the other side so

$2 x^{2} + 5 x + 4 = 0$ $2x^2 + 5x + 4=0$

$2 x^{2} = a$ $2x^2=a$
$5 x = b$ $5x=b$
$4 = c$ $4=c$