A culture of bacteria is growing at a constant rate of 5% an hour. If the culture started with 3000 bacteria at 6:00 a.m. on Tuesday, calculate the approximate time that the bacteria population will reach 72,000?

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A culture of bacteria is growing at a constant rate of 5% an hour. If the culture started with 3000 bacteria at 6:00 a.m. on Tuesday, calculate the approximate time that the bacteria population will reach 72,000?

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Answer 1 · 2016-02-17T12:32:48

$72, 000 = 3000 \times {(1 + 0.05)}^{x}$ $72,000 = 3000xx(1+0.05)^x$ solve for $x$ $" " x" "$ (hours from the start) and add them to the 06:00 start time and day.

Explanation:

The equation for exponential growth is:
$y = a {(1 + r)}^{x}$ $y = a(1+r)^x$
Where:
a = initial amount before measuring growth
r = growth/decay rate (often a percent)
x = number of time intervals that have passed

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A culture of bacteria is growing at a constant rate of 5% an hour. If the culture started with 3000 bacteria at 6:00 a.m. on Tuesday, calculate the approximate time that the bacteria population will reach 72,000?

1 Answer

Explanation:

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