How do you graph #f(x)=2 \cdot 3^x#?

1 Answer
Gió
Jan 14, 2015

Well, I would start by recognizing that the function will never become negative, i.e., for every value of #x# I may choose, #y# will always be positive.
So, basically, I'll have a graph in the first and second quadrant.
I'll now try to give values of #x# but choosing values that are "easy" to be calculated (try to avoid difficult stuff such as #x=125#, you won't calculate #3^125#!).
You can use:
#x=0# that gives you #y=2# (#3^0=1#);
#x=1# that gives you #y=6#;
And...
enter image source here

Or more formally:
graph{2*3^x [-5.165, 4.835, -0.96, 4.04]}

Related questions
See all questions in Exponential Growth
Impact of this question
3983 views around the world
You can reuse this answer
Creative Commons License