How do you convert 350.0 mL at 740.0 mm of Hg to its new volume at standard pressure?

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How do you convert 350.0 mL at 740.0 mm of Hg to its new volume at standard pressure?

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Answer 1 · 2016-02-10T19:28:34

Unlike gases, liquids don't compress appreciably, so the volume will be the same.

Answer 2 · 2016-02-10T19:35:00

We use Boyle's law: $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ , temperature and amount of gas constant. We would expect the volume to decrease slightly.

Explanation:

Given the relationship, $V_{2} = \frac{P_{2} V_{1}}{P_{1}}$ $V_2=(P_2V_1)/P_1$ , we can use non-standard units of pressure and volume, such as $m L$ $mL$ , and $m m$ $mm$ $H g$ $Hg$ . Ordinarily, we would have to convert these units into standard forms.

$V_{2} = (\frac{740}{760}) \times 350 \cdot m L$ $V_2 = (740/760)xx350*mL$ $=$ $=$ $? ?$ $??$ $m L$ $mL$

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How do you convert 350.0 mL at 740.0 mm of Hg to its new volume at standard pressure?

2 Answers

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