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What is the vertex of #y = 3(x - 2)^2 + 5#?

1 Answer

Feb 3, 2016

The vertex is at:(2, 5)

Explanation:

#y=a(x-h)^2+k# => equation of parabola in vertex form where: (h, k)is the vertex.
So in this case:
#y=3(x−2)^2+5# => the vertex is at:(2, 5)

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