What is the norm of #< 5 , -2, 3 >#?

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What is the norm of #< 5 , -2, 3 >#?

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Answer 1 · 2016-02-03T21:10:01

#\sqrt 38#

Explanation:

Just using pithagoras theorem you know #h=\sqrt(x_1^2+x_2^2+x_3^2+x_4^2+...)# as you are in three dimensional vectorial space, you stop at the third component.

so #|V|=\sqrt(5^2+(-2)^2+3^2)=\sqrt(38)#

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What is the norm of #< 5 , -2, 3 >#?

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