How do you graph using the intercepts for $- 18 x + 3 y = - 12$ $-18x + 3y = -12$ ?

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Answer 1 · 2016-02-02T22:24:29

Solve for the intercepts, then draw a straight line between them.

Solving for the intercepts yields:

$- 18 (0) + 3 y = - 12$ $-18(0)+3y=-12$
$y = - 4$ $y=-4$

$- 18 x + 3 (0) = - 12$ $-18x+3(0)=-12$
$x = \frac{2}{3}$ $x=2/3$

So plot the points $(0, - 4)$ $(0,-4)$ and $(\frac{2}{3}, 0)$ $(2/3,0)$ and draw a straight line connecting them.

How do you graph using the intercepts for -18x + 3y = -12−18x+3y=−12-18x + 3y = -12?