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What is #int xsin3x #?

1 Answer

Jan 30, 2016

#-(x^2cos3x)/3-1/9sin3x+c#

Explanation:

#intxsin3xdx#

#=x intsin3xdx-int[d/(dx)(x) intsin3 xdx]dx#

#=-x^2(cos3x)/3-int[(cos3x)/3]dx#

#=-(x^2cos3x)/3-1/3(sin3x)/3+c #

#=-(x^2cos3x)/3-1/9sin3x+c#

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