What is the equation of the line that passes through (-1,3) and is perpendicular to the line that passes through the following points: (6,-4),(5,2)?

1 Answer
Jan 6, 2016

Final answer: 6y=x+19 oe.

Explanation:

Defining line that passes through a:(-1, 3) as l_1.
Defining line that passes through b:(6, -4), c:(5, 2) as l_2.

Find the gradient of l_2.
m_2=(y_b-y_c)/(x_b-x_c)=(-4-2)/(6-5)=-6

l_2_|_l_1

So m_1=-1/m_2=-1/-6=1/6

Equation of l_1:
y-y_a=m_1(x-x_a)

y-3=1/6(x+1)

6y-18=x+1

6y=x+19

Or however you want it arranged.