How do you find the zeros, real and imaginary, of $y=x^2-x+17$ using the quadratic formula?

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Answer 1 · 2016-01-02T22:12:14

Calculate $Delta = b^2 - 4ac$ in order to know if which field the roots are in. The roots here are $(1 +- isqrt67)/2$

Here, $Delta = 1 - 4*17 = -67$ so this polynomial has 2 complex roots.

By the quadratic formula, the roots are given by the formula $(-b +- sqrtDelta)/2a$ .

So $x_1 = (1 - isqrt67)/2$ and $x_2 = bar(x_1)$ .

How do you find the zeros, real and imaginary, of y=x^2-x+17y=x^2-x+17 using the quadratic formula?