How do you find the amplitude, period, and shift for #y = -2sin (2x-3/2)?#?

1 Answer
Jim G.
Jan 2, 2016

#amplitude = 2, period = pi , shift = 3/2 to the right.

Explanation:

# a sin ( bx + c ) # defines the sine waveform
a represents the amplitude in this case a = 2 (the - means that the graph will be reflected in the x-axis)
the period of #sinx is 2pi radians#
the period of #sin2x = 2pi/2 = pi# ie period = # 2pi/b#

c denotes shift +c shifts c units left and -c c units to the right

hence c = 3/2 units to the right

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