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How do you solve the following system: #y = 3x – 12, 2x – 4y = 8#?

1 Answer

Dec 30, 2015

#x=4#, #y=0#

Explanation:

#color(white)xxy=3x-12,2x-4y=8#

#color(white)xx2x-4y=8<=>y=(x-4)/2#

#=>color(red)(3x-12)=(x-4)/2#
#=>color(blue)(x-4)=(x-4)/2#

#=>x-4=0#
#=>x-4color(green)(+4)=0color(green)(+4)#
#=>x=4#

#=>y=(color(red)4-4)/2#
#=>y=0#

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