How do you solve for y in #9-y=1.5x#?

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Answer 1 · 2015-12-29T21:48:07

#9 = 1.5x + y#
#y = 9 - 1.5x#

OR

#-y = 1.5x - 9#
#-1(-y) = -1(1.5x - 9)#
#y = 9 - 1.5x#

There are two methods for rearranging this equation.

Term Transaction

Add #y# to both sides of the equation:
#9 = 1.5x + y#
Subtract #1.5x# from both sides of the equation:
#9 - 1.5x = y" or "y = 9 - 1.5x#

Notice that the variables have simply changed places and reversed their signs.

Subtract 9 from both sides of the equation:
#-y = 1.5x - 9#
Multiply both sides of the equation by #-1#:
#-1(-y) = -1(1.5x - 9)#
#y = -1.5x + 9" or "y = 9 - 1.5x#