How do you solve 3r-4=4(r-3)3r−4=4(r−3)?

2 Answers
Topscooter
Dec 21, 2015

r = 8r=8.

Explanation:

You first develop the right side of the equality : 4(r-3) = 4r - 124(r−3)=4r−12. Now you switch all the rr at one side and the constants on the other side : 3r - 4 = 4(r-3) iff 3r - 4 = 4r - 12 iff 8 = r3r−4=4(r−3)⇔3r−4=4r−12⇔8=r.

Alan P.
Dec 21, 2015

Expand the right side, then add and subtract to get variable term on one side and constant term on the other.
r=8r=8

Explanation:

Given:
color(white)("XXX")3r-4=4(r-3)XXX3r−4=4(r−3)
Expand right side
color(white)("XXX")3r-4=4r-12XXX3r−4=4r−12
Subtract 3r3r from both sides
color(white)("XXX")-4=r-12XXX−4=r−12
Add 1212 to both sides
color(white)("XXX")8=rcolor(white)("XXXXXX")harr r=8XXX8=rXXXXXX↔r=8

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