How do you solve #3r-4=4(r-3)#?

2 Answers
Topscooter
Dec 21, 2015

#r = 8#.

Explanation:

You first develop the right side of the equality : #4(r-3) = 4r - 12#. Now you switch all the #r# at one side and the constants on the other side : #3r - 4 = 4(r-3) iff 3r - 4 = 4r - 12 iff 8 = r#.

Alan P.
Dec 21, 2015

Expand the right side, then add and subtract to get variable term on one side and constant term on the other.
#r=8#

Explanation:

Given:
#color(white)("XXX")3r-4=4(r-3)#
Expand right side
#color(white)("XXX")3r-4=4r-12#
Subtract #3r# from both sides
#color(white)("XXX")-4=r-12#
Add #12# to both sides
#color(white)("XXX")8=rcolor(white)("XXXXXX")harr r=8#

Related questions
Impact of this question
1494 views around the world
You can reuse this answer
Creative Commons License