Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve the system #x^2 - 2y = 1#, #x^2 + 5y = 29#?

1 Answer

Dec 18, 2015

#absx = 3#
#y = 4#

Explanation:

You can substract the 1st line to the 2nd one, which will make #x^2# disappear. So the 2nd line is now #7y = 28# and you now know that #y = 4#.

You replace #y# by its value in the 1st line of the system :

#x^2 - 2y = 1 iff x^2 - 8 = 1 iff x^2 = 9 iff abs(x) = 3#

Related questions

See all questions in Solving by Substitution

Impact of this question

1397 views around the world

You can reuse this answer
Creative Commons License