How do you factor the trinomial # x² + 3x - 10#?

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How do you factor the trinomial # x² + 3x - 10#?

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Answer 1 · 2015-11-20T14:49:25

first find the discriminant which is equal to #d=b^2 - 4ac#
then apply the formula #(-b+d^(1/2))/(2a)# and #(-b-d^(1/2))/(2a)# these will be the 2 factors; #a# is the coefficient of #x^2#, #b# of #x#, #c#c is the constant term

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How do you factor the trinomial # x² + 3x - 10#?

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