How do you simplify $\frac{x^{2} + x + 15}{x^{2} - 3 x}$ $(x^2+x+15)/(x^2-3x)$ ?

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How do you simplify $\frac{x^{2} + x + 15}{x^{2} - 3 x}$ $(x^2+x+15)/(x^2-3x)$ ?

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Answer 1 · 2015-11-19T18:51:11

$\frac{15}{- 4 x}$ $( 15)/( - 4x )$

Explanation:

When you see this equation:
$\frac{x^{2} + x + 15}{x^{2} - 3 x}$ $(x^2 + x + 15)/(x^2 - 3x)$

What you need to remember is that you see a $x^{2}$ $x^2$ on both sides of the fraction-line. This means you can cross them out, because they are equal on both sides.

So now your equation looks like this:
$\frac{x + 15}{- 3 x}$ $( x + 15)/( - 3x)$

Now as you can see, both sides of the fraction-line have a $x$ $x$ . So what you do is you take the smallest $x$ $x$ of the largest $x$ $x$ , so that you can remove the $x$ $x$

In this case, the smallest $x$ $x$ is the $x$ $x$ on the numerator and the biggest $x$ $x$ is the $- 3 x$ $- 3x$ on the denominator.

If you apply what I just said, your equation would be:
$\frac{x - x + 15}{- 3 x - x} = \frac{15}{- 4 x}$ $( x - x + 15)/( - 3x - x) = ( 15)/( - 4x )$

So the simplified version of $\frac{x^{2} + x + 15}{x^{2} - 3 x} = \frac{15}{- 4 x}$ $(x^2 + x + 15)/(x^2 - 3x) = ( 15)/( - 4x )$

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How do you simplify $\frac{x^{2} + x + 15}{x^{2} - 3 x}$ $(x^2+x+15)/(x^2-3x)$ ?

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Explanation:

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