How do you solve the following linear system $3x-2y=8, 4x-2y=9$ ?

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Answer 1 · 2015-11-19T16:29:22

x=1 and y=-5/2

3x-2y=8 →equation 1
4x-2y=9 →equation 2

Equation 1 - equation 2
3x-2y=8
- 4x-2y=9
﹏﹏﹏﹏﹏﹏﹏
-x = -1
x = 1

x=1 into equation 1 or you can also substitute to equation 2.

x=1 into equation 1

3(1)-2y=8
3-2y=8
-2y=8-3
-2y=5
-y=5/2
y=-5/2

How do you solve the following linear system 3x-2y=8, 4x-2y=9 3x-2y=8, 4x-2y=9 ?