How do you solve the following linear system: $x - 5 y = 3, y = 3 x + 2$ $x - 5y = 3, y= 3x + 2$ ?

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Answer 1 · 2015-11-16T16:39:16

x-5y=3⇨equation 1
y=3x+2⇨change x as the tittle
-3x+y=2⇨equation 2

x-5y=3⇨equation 1
-3x+y=2⇨equation 2

(Equation 1×3)
3x-15y=3→equation 3
-3x+y=2⇨equation 2

Equation 3 + equation 2

-14y=5
y=-5/14

Substitute value of y into x:

-3x-5/14=2
-42x-5=28
-42x=33
x=-33/42

How do you solve the following linear system: x - 5y = 3, y= 3x + 2 x−5y=3,y=3x+2x - 5y = 3, y= 3x + 2 ?