How do you solve the system $y = 2x + 1$ , $y = 3x - 7$ ?

Question

5524 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-15T18:30:32

2x + 1 = 3x - 7
1=x-7
x=8
y= 17

There are two equations explaining the value of y.
y is 2x + 1
y is also 3x - 7
Therefore, those values must be equal.

2x + 1 = 3x - 7

Continue till you get x= 8
Then substitute for x in any of those 2 equations.
y = 17

How do you solve the system y = 2x + 1 y = 2x + 1, y = 3x - 7y = 3x - 7?