How do you find the x and y intercepts for #y = 2x + 18#?

1 Answer
Tony B
Nov 14, 2015

The plot crosses the y-axis when x=0 and it crosses the x-axis when y=0. So by substitution of 0 for one you find the value of the other by manipulation of the equation

Explanation:

If you meant to ask more than just how:

When #x=0#
#y=(2 times 0) + 18#

so the y-axis intercept is at #(x,y)->(0,18)#
For a strait line graph it is always at the value of the constant.

So at the x-axis intercept #y=0#

#0=2x+18#
#2x= -18#
#x= (-18)/2 = -9#

So the x-axis intercept is at #(x,y)-> (-9,0)#

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