How do you solve $7 - 7 x = (4 x + 9) (x - 1)$ $7 - 7x = (4x + 9)(x - 1)$ ?

Question

How do you solve $7 - 7 x = (4 x + 9) (x - 1)$ $7 - 7x = (4x + 9)(x - 1)$ ?

1 Answer

Impact of this question

2456 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-12T15:14:35

x = -4 , 1

Explanation:

7 - 7x = (4x + 9) (x - 1)
or, 7 - 7x = 4x((x-1) + 9(x-1)
or, 7 - 7x = 4 $x^{2}$ $x^2$ -4x +9x -9
or, 0 = 4 $x^{2}$ $x^2$ +5x +7x-7-9
or, 4 $x^{2}$ $x^2$ +12x-16 = 0
0r, 4 $x^{2}$ $x^2$ +(16-4)x-16 = 0
or, 4 $x^{2}$ $x^2$ +16x -4x-16 = 0
or, 4x(x+4) - 4(x+4) = 0
or, (x+4) (4x -4) = 0
Either (x+4) = 0
x = -4
Or, (4x-4) = 0
or, 4x =4
or, x = $\frac{4}{4}$ $4/4$
or, x = 1
Hence x = -4 , 1

Science

Math

Humanities

... and beyond

How do you solve $7 - 7 x = (4 x + 9) (x - 1)$ $7 - 7x = (4x + 9)(x - 1)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 7 - 7x = (4x + 9)(x - 1)7−7x=(4x+9)(x−1)7 - 7x = (4x + 9)(x - 1)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $7 - 7 x = (4 x + 9) (x - 1)$ $7 - 7x = (4x + 9)(x - 1)$ ?