How do you find the important parts of the equation to graph the function $y = {(x - 3)}^{2} + 2$ $y=(x-3)^2+2$ ?

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Answer 1 · 2015-11-09T13:19:53

y-intercept = 2
x-intercept = 3

x- intercept is supposed to be -3 right, but we need to change the symbol.

it is actually like this;
x-3=0
x=3

if u have any question, feel free to ask ok!

How do you find the important parts of the equation to graph the function y=(x−3)2+2y=(x-3)^2+2?