What is the amplitude, period and the phase shift of #y=- 2/3 sin πx#?

1 Answer
Rashi J.
Nov 6, 2015

Amplitude: #2/3#
Period: #2#
Phase shift: #0^\circ#

Explanation:

A wave function of the form #y=A*sin(\omega x + \theta)# or #y=A*cos(\omega x + \theta)# has three parts:

  1. #A# is the amplitude of the wave function. It does not matter if the wave function has a negative sign, amplitude is always positive.

  2. #\omega# is the angular frequency in radians.

  3. #theta# is the phase shift of the wave.

All you have to do is identify these three parts and you're almost done! But before that, you need to transform your angular frequency #omega# to the period #T#.

#T=\frac{2pi}{omega}=\frac{2pi}{pi}=2#

Related questions
See all questions in Amplitude, Period and Frequency
Impact of this question
2179 views around the world
You can reuse this answer
Creative Commons License