How do you simplify # cot(x) *sec(x)#?

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Answer 1 · 2015-10-26T15:44:34

#csc(x)#

#[1]" "cot(x)*sec(x)#

Quotient Identity: #cot(x)=cos(x)/sin(x)#

#[2]" "=cos(x)/sin(x)*sec(x)#

Reciprocal Identity: #sec(x)=1/cos(x)#

#[3]" "=cos(x)/sin(x)*1/cos(x)#

#[4]" "=cancelcos(x)/(sin(x)cancelcos(x))#

#[5]" "=1/sin(x)#

Reciprocal Identity: #1/sin(x)=csc(x)#

#[6]" "=color(blue)(csc(x))#