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How do you find the derivative of #f(x)=1/(x-1) #?

1 Answer

Oct 23, 2015

#f'(x)=-1/(x-1)^2#

Explanation:

#f(x)=1/(x-1)=(x-1)^-1#

Using the rule: #f(x) =x^n => f'(x)=nx^(n-1)# and chain rule:

#f'(x)=-1*(x-1)^-2 * (x-1)' = -(x-1)^-2 = -1/(x-1)^2#

#f'(x)=-1/(x-1)^2#

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