How do you simplify $\frac{x^{2} + 3 x - 18}{x^{2} - 36}$ $(x^2+3x-18)/(x^2-36)$ ?

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How do you simplify $\frac{x^{2} + 3 x - 18}{x^{2} - 36}$ $(x^2+3x-18)/(x^2-36)$ ?

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Answer 1 · 2015-10-17T07:43:36

$\frac{x^{2} + 3 x - 18}{x^{2} - 36}$ $(x^2+3x-18)/(x^2-36)$
= $\frac{x^{2} + 6 x - 3 x - 18}{(x + 6) (x - 6)}$ $(x^2+6x-3x-18)/((x+6)(x-6))$
= $\frac{x (x + 6) - 3 (x + 6)}{(x + 6) (x - 6)}$ $(x(x+6)-3(x+6))/((x+6)(x-6))$
= $\frac{(x + 6) (x - 3)}{(x + 6) (x - 6)}$ $((x+6)(x-3))/((x+6)(x-6))$
= $\frac{x - 3}{x - 6}$ $(x-3)/(x-6)$

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How do you simplify $\frac{x^{2} + 3 x - 18}{x^{2} - 36}$ $(x^2+3x-18)/(x^2-36)$ ?

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How do you simplify $\frac{x^{2} + 3 x - 18}{x^{2} - 36}$ $(x^2+3x-18)/(x^2-36)$ ?