What is the antiderivative of #4/x^2#? thanks!?

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Answer 1 · 2015-09-17T07:42:39

ant derivative is indefinite integral
#int# #4/x^2# #dx#
=#4int##1/x^2dx#
=#4int##x^-2dx#
=#4# #x^-1/-1##+c#
=#-4/x+c#