How do you write ${log}_{8} 64 = 2$ $log_8 64 = 2$ in exponential form?

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Answer 1 · 2015-09-11T12:57:04

$8^{2} = 64$ $8^2 = 64$

${log}_{a} b = c$ $log_a b = c$ can be rewritten as $a^{c} = b$ $a^c = b$ . This is the exponential form.

So, ${log}_{8} 64 = 2$ $log_8 64 = 2$ can be rewritten as $8^{2} = 64$ $8^2 = 64$ ,

One mnemonic you can use, is that you can read
${log}_{a} b$ $log_a b$
as "the value you raise $a$ $a$ to to get $b$ $b$ ."

How do you write log_8 64 = 2log864=2log_8 64 = 2 in exponential form?