What volume of ice would you have if you had #"1 L"# of water that froze?

2 Answers
Doreen O.
Aug 14, 2015

Density is equal to mass divided by volume. So volume would be equal to mass divided by density. Assuming mass stays at 1 liter which is 1000 grams and the density of ice is about 0.934 g/ml than the volume would be 1070.66 ml or
1.07066 liters.

Ernest Z.
Aug 14, 2015

The volume of ice would be #"1091 cm"^3#.

Explanation:

The density of water at 0 °C is #"0.9998 g/cm"^3#.

If you had 1 L of water at that temperature, its mass would be

#M = 1000 color(red)(cancel(color(black)("cm"^3))) × "0.9998 g"/(1color(red)(cancel(color(black)("cm"^3)))) = "999.8 g"#

The density of ice at 0 °C is #"0.9162 g/cm"^3#.

The volume of 998.8 g of ice at 0 °C is

#V = 998.8 color(red)(cancel(color(black)("g"))) × ("1 cm"^3)/(0.9162 color(red)(cancel(color(black)("g"))))= "1091 cm"^3#

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