How do you solve #5-2y=15#?
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"What is the equation of a neutralization reaction between sodium hydroxide and hydrochloric acid?"
1 Answer
Jun 18, 2015
y = -5
Explanation:
5 - 2y = 15
subtracting 5 form both the sides;
5-2y -5 = 15 -5
-2y = 10
divide both the sides by -2
-2y / -2 = 10 / -2
y = -5
