How do you find the point-slope form of the equation of the line passing through the point (-1, 2) and has slope -3?

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How do you find the point-slope form of the equation of the line passing through the point (-1, 2) and has slope -3?

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Answer 1 · 2015-05-30T07:53:18

The main formula of a line is;
#y=ax+b#

We should use the point to find the real equation. If we use (-1,2) point;
#y= ax+b => 2=-a+b#;
a is the slope of the equation, we found that as #-3#;
#2=(-3*-1) + b => 2=3 +b => b=-1#;
So the equation of the line will be;
#y=ax+b => ul (y= -3x-1)#

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How do you find the point-slope form of the equation of the line passing through the point (-1, 2) and has slope -3?

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