How do you find the point-slope form of the equation of the line passing through the points x(3, 2) and y(5,10)?

1 Answer
Elvan Burcu K.
May 30, 2015

First we have to find the slope of the equation. To find the slope we have to do;
#(y2-y1)/(x2-x1)# For our question slope is;

#(10-2)/(5-3) = 8/2 = 4#

The main formula of a line is;
#y=ax+b#

We should use one point to find the real equation. If we use (3,2) point;
#y= ax+b => 2=3a+b#;
a is the slope of the equation, we found that as #4#;
#2=(3*4) + b => 2=12 +b => b=-10#;
So the equation of the line will be;
#y=ax+b => ul (y= 4x-10)#
We can check if our equation is right or not with other given point;
#(5,10) => y=4x-10 => 10=(4*5)-10 => 10=20-10 => 10=10#enter image source here
So the equation is correct :)

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