How do you find the point-slope form of the equation of the line passing through the points (4,2), (-4, -2)?

1 Answer
Elvan Burcu K.
May 30, 2015

First we have to find the slope of the equation. To find the slope we have to do;
#(y2-y1)/(x2-x1)# For our question slope is;

#(-2-2)/(-4-4) = (-4)/-8 = 1/2#

The main formula of a line is;
#y=ax+b#

We should use one point to find the real equation. If we use (4,2) point;
#y= ax+b => 2=4a+b#;
a is the slope of the equation, we found that as #1/2#;
#2=(4*1/2) + b => 2=2 +b => b=0#;
So the equation of the line will be;
#y=ax+b => ul (y= x/2)#
We can check if our equation is right or not with other given point;
#(-4,-2) => y=x/2 => -2=-4/2 => -2=-2 #enter image source here
So the equation is correct :)

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