How do you solve the system #−3x + y = 2# and #4x + 2y = 4#?

Question

How do you solve the system #−3x + y = 2# and #4x + 2y = 4#?

1 Answer

Impact of this question

2080 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-29T09:04:41

#-3x + y =3 => y = 3 +3x # ;
#4x + 2y = 4 => 4x + 2*(3+3x)= 4 => 4x+6+6x=4 #
# => 10x +6 =4 => 10x =-2 => x=-2/10=-1/5 #
#y=3+3x => y=3+3*(-1/5) => y= 3-3/5 => y= 15/5 - 3/5 #
# y= 12/5 #

Science

Math

Humanities

... and beyond

How do you solve the system #−3x + y = 2# and #4x + 2y = 4#?

1 Answer

Related questions

Impact of this question