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How do you write the quadratic in vertex form given #y=3x^2+6x-1#?

1 Answer

May 9, 2015

The vertex form is:

#y-y_v=a(x-x_v)^2#.

So:

#y=3(x^2+2x)-1rArry=3(x^2+2x+1-1)-1rArr#

#y=3(x^2+2x+1)-3-1rArry=3(x+1)^2-4rArr#

#y+4=3(x+1)^2#.

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