How do you factor by grouping #2x^3 - x^2 - 6x + 3#?

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Answer 1 · 2015-04-30T08:58:37

we are given, 2#x^3# #-# #x^2# #-#6#x# #+# 3

The first two terms have #x^2# in common and the last two terms have 3 in common:

taking out the common terms:

#=# #x^2# (2#x# #-# 1) #+# 3 (#-#2#x# #+#1)

#=# #x^2# (2#x# #-# 1) #-# 3 (2#x# #-#1)

making groups of two,

#=# ( #x^2# #-#3) (2#x# #-# 1)