How do you solve #6+2cos(theta)=5#?

1 Answer

Apr 19, 2015

#6 + 2 cos x = 5 --> 2cos x = -1 --> cos x = -1/2#
Trig table gives answer: #x_1 = 2pi/3.#
Trig unit circle gives another arc x that has the same cos value:
#x_2 = 4pi/3.#
Within the interval (#0, 2pi#), there are 2 answers: #2pi/3# and #4pi/3#

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How do you solve #6+2cos(theta)=5#?

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