How do you solve for y : #4x- 3y = 12#?

Question

30939 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-10T11:14:34

#4x-3y=12#

Rearrange the equation so that #3y# is isolated from other values:

#4x-12=3y#

Now, we can find #y# by dividing the all values in the equation by 3.

#(4x-12)/3=(3y)/3#

#4/3x-4 = y#

#y=4/3x-4#