What is the final temperature of water if it used 520 J from 52 degrees C?

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Answer 1 · 2015-03-27T13:05:02

The final temperature depends on the mass of the water, and the mass must be sufficient that the water does not boil.

But we can do a general calculation.

#q = mcΔT#

#ΔT = T_2 –T_1 = q/(mc)#

#T_2 = T_1 + q/(mc)#

Using your values, we get

#T_2 = "52 °C" + (520 cancel("J"))/(m × 4.184 cancel("J")"g⁻¹°C⁻"¹)#

#T_2 = "52 °C" + "124 g°C"/m#

Now you can insert your own value of #m# and calculate the value of #T_2#.