Your chemistry professor gives you a 5 gallon jar containing 2 gallons of 40% alcohol. He asks you to reduce the concentration to 25%. How much water must you add to the jar?

1 Answer
Dec 20, 2015

33 gallons

Explanation:

The context can be modelled by a general equation:

% "alcohol"="gal alcohol"/"gal solution"%alcohol=gal alcoholgal solution

Using the example, 40% "alcohol"=("2 gal alcohol")/("5 gal")*100%40%alcohol=2 gal alcohol5 gal100%, we can set up another equation to solve for the number of galloons added.

Let xx be the number of gallons added.

25% "alcohol"=("2 gal alcohol")/("5 gal water"+"x gal water")*100%25%alcohol=2 gal alcohol5 gal water+x gal water100%

25% "alcohol"color(red)(-:100%)=("2 gal alcohol")/("5 gal water"+"x gal water")*100%color(red)(-:100%)25%alcohol÷100%=2 gal alcohol5 gal water+x gal water100%÷100%

0.250.25 "alcohol"=("2 gal alcohol")/("5 gal water"+"x gal water")alcohol=2 gal alcohol5 gal water+x gal water

0.250.25 "alcohol"*("5 gal water"+"x gal water")="2 gal alcohol"alcohol(5 gal water+x gal water)=2 gal alcohol

0.250.25 "alcohol"color(red)(-:0.25)alcohol÷0.25color(red)("alcohol")*("5 gal water"+"x gal water")="2 gal alcohol"color(red)(-:0.25)alcohol(5 gal water+x gal water)=2 gal alcohol÷0.25color(red)("alcohol")alcohol

"5 gal water+"x"5 gal water+x "water"water "gal"="8gal=8 "gal"gal

"x gal water"x gal water== "3 gal water"3 gal water

:., 3 gallons of water must be added.