You roll 2 dice. What is the probability that the sum of the die is even and one shows a 3?

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Answer 1 · 2017-01-31T06:13:53

$= \frac{5}{36}$ $=5/36$

we also can write as
$(1,1),...(1,6)$ ,
$(2,1),...(2,6)$ ,
$(3,1),...((3,6)$ ,
$(4,1),...(4,6)$ ,
$(5,1),...(5,6)$ , and
$(6,1),...(6,6)$

and it total is $36$ .
therefore $n(xi) =36$

Let say that $A$ is an outcome for which a 3 must one show and their sum is even are ( $3,1),(3,3),(3,5), (1,3) and(5,3)$ , therefore $n(A) = 5$

Probability A = $(n(A))/(n(xi))$

$=5/36$

Answer 2 · 2017-01-31T06:21:36

$p=5/36$

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There are 36 outcomes. Of which 5 are favourable.

Probability = Number of favourable outcomes)/ Total number of outcomes

$p=5/36$