You are given two sides of a triangle, a = 4.5 and b = 6, the angle between them is 35 degrees, how do you find the third side and the area of the triangle.?

Question

9488 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-01T11:27:45

Third side is #3.47# unit and area of triangle is #7.74# sq.unit.

Sides #a=4.5 , b=6# and their included angle #/_C = 35^0#

Cosine rule: (for all triangles) #c^2=a^2 + b^2 − 2 a b cos(C) #

#:. c^2=4.5^2 + 6^2 − 2*4.5*6*cos(35)# or

#c^2~~12.02 :. c ~~ 3.47 (2dp)#

Sides #a=4.5 , b=6# and their included angle

#/_C = 35^0#. Area of the triangle is #A_t=(a*b*sin C)/2#

#:.A_t=(4.5*6*sin 35)/2 ~~ 7.74# sq.unit

Area of the triangle is #7.74# sq.unit.

Third side is #3.47# unit and area of triangle is #7.74# sq.unit

[Ans]