Y=x^2cos(x)/sin(x) find dy/dx ? pls help

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Answer 1 · 2018-03-29T19:51:52

#=-x^2csc^2x+2xcotx#

According to socratic format your question is:

#y=x^2cosx/sinx#

#y=x^2cotx#

#=>(dy)/(dx)=x^2d/(dx)(cotx)+cotxd/(dx)(x^2)#

#=x^2(-csc^2x)+cotx(2x)#

#=-x^2csc^2x+2xcotx#

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