Y varies inversely as the cube of x Given that y = 24 when x = 2 find the value of x when y = -3 How do I solve this?

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Answer 1 · 2018-04-22T18:05:13

#x=-4#

Inverse variation will be modeled by:
#y=k/x^3#

Solving for #k#:
#24=k/2^3#

#k= 24*8#

#k=192#

#y=k/x^3#

Solving for #x#:
#-3=192/x^3#

#x^3= 192/-3#

#x= root(3)(-64)#

#x=-4#