Write The Equation Of a Line That Contains The Points (2,5) And (-2,-1) ?

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Answer 1 · 2018-03-17T00:00:01

First, we need to find the slope of the line using the following formula.
$(y2-y1)/(x2-x1)$

$= (-1-5)/(-2-2)$
$= (-6)/(-4)$
$= 3/2$

Therefore, the slope of the line is $3/2$ .

Next, we need to find the y-intercept by substituting the following using the slope and one of the given points.
(2,5)

$y = mx+b$
$5= 3/2 (2)+b$
$5= 6/2 +b$
$5-6/2 =b$
$4/2 =b$
$b=2$

Therefore, the y-intercept is $2$ .

Lastly, write the equation.
$y = 3/2x +2$