Write an equation for a line that is parallel to the equation y= -9. The line must pass through the points (4, -11). How do I do this?

1 Answer
Gió
Sep 11, 2015

I should get #y=-11#

Explanation:

In this cas you are lucky...your original line is perfectly horizontal (slope #=0#)!!!
So, to be parallel you need another horizontal line that passes through #-11# i.e.:
#y=-11#

In general you can write the equation of a line as:
#y=mx+c#
where:
#m=# slope
#c=# y-intercept
so here you need:
slope #=m=0#
y-intercept #=c=-11#

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